All-on-4 Dental Implants Cost in Boise, ID (2026)
All-on-4 in Boise, ID averages $20,200 per arch ($11,020 – $32,130). Metro-adjusted pricing for Boise. Use the calculator below for a personalized estimate.
Dental Implant Cost Calculator
Estimated cost in Idaho
$1,800 – $6,930
Average: $3,960
Includes implant, abutment, and crown where applicable. Actual quotes vary by provider.
All-on-4 Price Breakdown in Boise, ID
- Four titanium implants: $5,050 – $8,080
- Fixed full-arch prosthesis: $9,090 – $13,130
- Extractions, sedation, temporaries: $800 – $3,500
Estimates based on ADA survey data, regional dental fee reports, and 2026 market adjustments.
| Procedure | Low | Average | High |
|---|---|---|---|
| Single implant | $1,100 | $2,750 | $5,050 |
| All-on-4 (full arch) | $11,020 | $20,200 | $32,130 |
| Crown (per tooth) | $730 | $1,290 | $2,020 |
| Bone graft (if needed) | $370 | $730 | $1,380 |
Boise, ID vs. national average (single implant): national mid $3,000. Last updated: 2026-03-01.
Frequently Asked Questions
How much does All-on-4 cost in Boise, ID?
In Boise, ID, All-on-4 typically ranges from $11,020 to $32,130, averaging $20,200 per arch in 2026.
Does insurance cover All-on-4?
Most dental plans classify All-on-4 as major restorative work. Coverage is often limited to annual maximums ($1,000–$2,500) unless medically necessary.
Is All-on-4 cheaper than individual implants?
For a full arch, All-on-4 is usually less expensive than placing 8–10 individual implants with separate crowns.